Question

two beads of masses m1 and m2 are threaded on a smooth circular wire of radius 'a' fixed in a vertical plane. B is stationary at the lowest point when A is gently dislodged fro rest at the highest point. A collides with B at the lowest point. The impulse given to B due to collision is just great enough to carry it to the level of the centre of the circle while A is immediately brought to rest by the impact. Find m1:m2

Answer 1

Explanation:

If velocity of B is zero at center position

Then

V

B

2

−u

B

=−2ga

u

B

=

2ga

At bottom velocity A is V

A

V

A

2

−0=2g(2a)

V

A

=

4ga

As shown if figure 1(b) momentum is conserved

m

A

V

A

=m

B

V

B

m

1

4ga

=m

2

2ga

m

2

m

1

=

2

1