Chemistry, asked by shivam27562, 1 year ago

Two beakers A and B are taken. Beaker A is filled with normal water and beaker B is filled with a concentrated solution of sugar. A few raisins are put in both the beakers.
(i) What will happen to the raisins put in both the beakers?
(ii)What will be the right observation. What if we keep iron nails instead of raisins in water.​

Answers

Answered by sujan2002
8

1)the rasin in the beaker a shrinks in size

2) the rasins in beaker B swells

this happens because of a process called osmosis

OSMOSIS:

The movement of substances from high concentration to low concentration is known as osmosis.

..in beaker A the rasins are more concentrated than normal water so the water from it flows out and it shrinks in size

..in beaker B the rasins are less concentrated than sugar solution hence the water moves from sugar solution to rasins and it swells

HOPE IT HELPS U BUDDY:)

Answered by anupamchaudhary
0

Answer:

Two beakers A and B contain plain water and concentrated sugar solution respectively. Equal number of dry raisins are kept in them for a few hours and then taken out.

(i) Explain the reason for the difference in the physical appearance of raisins which were taken out of the two beakers.

(ii) On the basis of above observation, categorise the two solutions as hypotonic and hypertonic.

Explanation:

hope it will help you

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