Chemistry, asked by anujmalviya2004, 1 year ago

two beakers A and B contain iron(II) sulphate solution in the beaker Aa small piece of copper is placed and in the beaker b a small piece of zinc is placed what will be observed​

Answers

Answered by Harishankar27
8

Answer:

There will be a reaction in test tube B

Explanation:

This is because zinc is more reactive than iron so it will replace iron from its salt solution

And copper being less reactive than iron will not be able to displace iron from its salt solution

Answered by lakshayjain1701lj
7

Answer:

THE BEAKER A IN WHICH COPPER IS ADDED WILL NOT SHOW ANY REACTION.

THE REASON IS THAT COPPER IS LESS REACTIVE THAN IRON. HENCE IT WILL NOT SHOW ANY REACTION WITH IRON SULPHATE.

THE BEAKER A WILL SHOW REACTION.

AS ZINC IS MORE REACTIVE THAN IRON.

SO IT WILL REPLACE IRON FROM IT ITS SULPHATE AND ZINC SULPHATE WILL BE FORMED ALONG WITH IRON. IT'S AN EXAMPLE OF DISPLACEMENT REACTION.

HOPE IT HELPS U ...HAVE A NICE DAY

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