Two beakers A and B contain Iron (II) sulphate solution. In the beaker A is placed a small piece of copper and in the beaker B is placed a small piece of zinc. It is found that a grey deposit forms on the zinc but not on the copper. What can be concluded from these observations?
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Answer:
Zn has more reactivity than Fe and will displace it where as Cu has less reactivity than Fe and will not displace it. in simple words in TERMS OF REACTIVITY
Zn>Fe>Cu
Explanation:
so there are two beakers containing fe0 solution.
in beaker A we have added cu and cu + fe0 will be there. and in beaker B zn+ fe0 will be there . so in beaker B Displacement reaction will take place and zn will replace fe due to it's more reactivity. but cu fails to displace to fe from fe0 in beaker A and no reaction takes place in beaker A.
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