two beakers a and b containing hot and cold water respectively are taken. a drop of ink is added in both. Name the phenomenon taking place in the above activity.
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He must have observed that the crystal of copper sulphate in beaker A has diffused evenly than in beaker B. This describes the phenomenon of diffusion. On heating, diffusion becomes faster because the kinetic energy increases. So the particles of CuSO4(copper sulphate) must have diffused with the particles of hot water quickly than in the cold water.
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centrifugation
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this is the answer
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