Two bells started at same time. After1 Hr it was noticed that first bell is 3.6min faster and second one is 2.4 min slower. Then at what time they will again ring together
Answers
Answer:
50 Hrs
Step-by-step explanation:
Two bells started at same time. After1 Hr it was noticed that first bell is 3.6min faster and second one is 2.4 min slower. Then at what time they will again ring together
After1 Hr = 60 mins
one bell = 3.6 min Faster
Second one = 2.4 min Slower
Time Difference in Both = 3.6 + 2.4 = 6 Mins
To ring together at least Their time Difference should be 1 hr or multiple of that = 60 min or Multiple of That
Multiple of 10 hrs
After 10 Hrs Faster will Gain = 36 min
& Slower will Loose = 24 mins
But to ring together they both must loose or gain Time in multiple of 60 mins
36 = 12 * 3 24 = 12 * 2
LCM = 12 60/12 = 5
=> 10*5 = 50 hrs
in 50 hrs one will loose = 50*2.4 = 120 mins = 2hrs
one will gain = 50*3.6 = 180 mins = 3 hrs
They Will ring together with a gap of 5 hrs
After 50 Hrs they will ring together