Question

Two bicycle riders A and B make a 36 km trip and
reach the destination at the same time. While cyclist
A travelled non-stop at an average speed of
18 km/h, cyclist B travelled with a lunch break of
30 ming The average speed of B for the time interval
he was in motion is​

Answer 1

Answer:

14.4 km/hr

Explanation:

s=d/t

t=d/s

=36/18

2 hrs

then 2.5 hr is there

s=d/t

=36/2.5

14.4

Answer 2

Answer:

24 km/h

Explanation:

For A

d=36 km

v=18 km/h

from t=d÷v we get

t=2 hrs

acc to que A and B takes same time to reach destination.

For B

d=36 km

t= 1.5 hrs (since he takes a break of half hour and A and B reaches at same time so he get only 1.5 hour to complete journey)

using v=d÷t we get

36÷1.5=24 km/h