Two bikes A and B are moving with the velocity 60 km/hr towards north and 40 km/hr and south respectively. If both bikes started from the same place and same time, calculate the distance between them after three minutes.
Answers
Answer:
5 km
Explanation:
Suppose Bike A and bike B are moving from point O with the velocity 60 km/hr towards north and 40 km/hr towards south respectively.
A------------O---------B
here,we have to calculate that distance between A and B
therefore,
speed of bike A= 60km/hr
speed of bike B=40km/hr
then,
speed of bike A= (60/60) km/min
= 1 km/min
because 1hr = 60min
And
speed of bike B= (40/60)km/min
= (2/3) km/min
We know that,
v (velocity)= d (distance)/ t (time)
therefore, d=v×t (we will use this formula)
then,
after 3 minutes,distance of bike A from point O
AO
= 1×3
=3 km
and
after 3 minutes, distance of a bike B from point O
OB
=(2/3)×3
=2 km
therefore, AB=AO+OB=3+2=5 km
which is required answer.