Two bikes get closer by 10 m every second while travelling in the opposite directions. They get closer
by 1 m in every second while travelling in the same directions. The speeds of the two bikes will be
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Hey Dear,
◆ Answer -
v1 = 5.5 m/s
v2 = 4.5 m/s
● Explanation -
Let v1 & v2 be velocities of two bikes.
When two bikes travel in same direction, relative velocity is given by -
v1 + v2 = 10 m/s ...(1)
When two bikes travel in opposite direction, relative velocity is given by -
v1 - v2 = 1 m/s ...(2)
Adding (1) & (2),
(v1 - v2) + (v1 - v2) = 10 + 1
2v1 = 11
v1 = 11/2
v1 = 5.5 m/s
Putting this in (1),
v1 + v2 = 10
6.5 + v2 = 10
v2 = 10 - 6.5
v2 = 4.5 m/s
Therefore, velocities of two bikes are 5.5 m/s & 4.5 m/s
Thanks for asking..
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