Two billiard balls each of mass 0.05kg moving in opposite direction with speed of 6m/s collide and rebound with the same speed. What is the impulse imparted to each ball due to the other?
plz answer with solution
Answers
Answer:
Hey !
Explanation:
Mass of each ball =0.05kg
Initial velocity of each ball =6m/s
Magnitude of the initial momentum of each ball, Pi=mvi=0.05×6=0.3 kg m/s
After collision, the balls change their directions of motion without changing the magnitudes of their velocity.
Final momentum of first ball, P1f=−0.3 kg m/s
Final momentum of second ball, P2f=0.3 kg m/s
Impulse imparted to first ball = P1f−P1i=−0.3−0.3 kg m/s=−0.6 kg m/s
Impulse imparted to second ball = P2f−P2i=0.3−(−0.3)=0.6 kg m/s
The negative sign indicates that the impulses imparted to the balls are opposite in direction.
I Hope it Helps You ❤
Answer:
Mass of each ball( m) = 0.05 kg
Initial velocity of each ball(v) = 6 m/s
We know that momentum = mv
Therefore, magnitude of the initial momentum of each ball( p₁) = 0.3 kg m/s
Please note that after collision, the balls change their directions of motion without changing the magnitudes of their velocity.
Therefore, final momentum of each ball( p₂) = -mv= –0.3 kg m/s
Impulse imparted to each ball = change in the momentum of the system = (p₂ – p₁) = –0.3 – 0.3 = –0.6 kg m/s
The negative sign indicates that the impulses imparted to the balls are opposite in direction.