Question

Two billiard balls with mass 1.0 kg each are travelling towards each other. The first one is moving at a velocity of 3 m/s, while the other one moves at a velocity of -2m/s. After the collision, one billiard ball moves to the left at a speed of 2 m/s. What is the speed of the other ball? ​

Answer 1

Answer:

1m/s towards right

Explanation:

m1v1+m2v2=m1u1+m2u2

2+v2=3-2

v2=1-2

v2=-1m/s towards left

=1m/s towards right

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Answer 2

Answer:

The speed of the other ball is 1m/s in the right direction.

Explanation:

Given:

Mass of the balls(m)=1kg

Initial velocity of ball one(u1)=3m/s

Initial velocity of the ball two(u2)=-2m/s

Final velocity of the ball one(v1)=2m/s

To find:

Final velocity of the ball two(v2)=?

Solution:
We know that,

Momentum=Mass×Velocity

As the per the law of conservation of momentum,

Momentum before collision=Momentum after collision

m(u1+u2)=m(v1+v2)

3-2=2+v2

1=2+v2

∴v2=-1m/s

Therefore, the speed of the other ball is 1m/s in the right direction.