Question

Two biscuit of Electrum have
their total weight equivalent
to 60 kg. The first piece
contains 10 kg of pure gold
and the second piece
contains 8 kg of pure gold.
What is the percentage of
gold in the first piece of
Electrum if the second piece
contains 15 per cent more
gold than the first?​

Answer 1

Answer:

10+8 =18

1st(10by18 ×100)

10×50=500

500by9=55.5%

Answer 2

Answer:

25%

Step-by-step explanation:

Let percentage of pure gold in two pieces be x % and (x+15)%

Weight of first piece = $\frac{10 \times 100}{x}$

Weight of Second piece = $\frac{8 \times 100}{x+15}$

Now we are given that Two biscuit of Electrum have  their total weight equivalent  to 60 kg.

So, $\frac{10 \times 100}{x}+\frac{800}{x+15}=60$

$x=-10,25$

Since percentage cannot be negative

So, the percentage of  gold in the first piece is 25%