Question

two block each of have mass m lie on smooth table . they are attach to two other mass one with 3 kg and another with 2kg . the pulley and string is light , an object 'o' is kept at rest on the table . the side AB of one block & side CD of another block has reflecting surface . the acceleration of the image if the object formed by both reflecting surface w.r.t each other

Answer 1

First take the system and find the acceleration of system (each blocks)

the accn a = (M1 - M2)g / (M1 +M2)

SO, ACCLN = g/3

now after system is released the bigger block is stopped for a moment after 1 sec, hence after 1 sec ..

the vel V1 of the smaller block = g/3 * 1= g/3 m/sec

now again the system is free .so,all the thread which was winding now gets tightened ..

the string will be tight again when displacement of both particles are equal in magnitude.

So gT/3 -(1/2)gT2 = (1/2)gT2

Solving this we get T = 1/3 sec

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Answer 2

Explanation:

refer the attachment

I hope you are satisfied by my answer