Question

Two block of masses 3kg and 6kg are connected to the two ends of of light extensible spring passes over a frictionless pulley . If the masses ate released,then find the acceleration of the masses​

Answer 1

Answer:

9

Explanation:

g*t1+t2

10*3+6

10*9

90

Answer 2

Given :

Two blocks of masses 3kg and 6kg are connected to the two ends of light string passes over a frictionless pulley$.$

To Find :

Common accelerarion of the system$.$

SoluTion :

Such question can be solved by Newton's second law of motion. As per this law, Net force acts on the system is defined as the product of mass and acceleration$.$

Force on block of mass 3kg = 3g

[In downward direction]

Force on block of mass 6kg = 6g

[In downward direction]

➝ Fnet = M × a

➝ (6g - 3g) = (6 + 3) × a

➝ 3g = 9a

➝ a = 3g/9

➝ a = g/3 = 3.33m/s²