Two block of masses 3kg and 6kg are connected to the two ends of of light extensible spring passes over a frictionless pulley . If the masses ate released,then find the acceleration of the masses
Answers
Answered by
0
Answer:
9
Explanation:
g*t1+t2
10*3+6
10*9
90
Answered by
11
Given :
Two blocks of masses 3kg and 6kg are connected to the two ends of light string passes over a frictionless pulley
To Find :
Common accelerarion of the system
SoluTion :
Such question can be solved by Newton's second law of motion. As per this law, Net force acts on the system is defined as the product of mass and acceleration
Force on block of mass 3kg = 3g
[In downward direction]
Force on block of mass 6kg = 6g
[In downward direction]
➝ Fnet = M × a
➝ (6g - 3g) = (6 + 3) × a
➝ 3g = 9a
➝ a = 3g/9
➝ a = g/3 = 3.33m/s²
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