Question

Two block of masses m1 and m2 are placed in contact with each other on fraction less horizontal surface. a constant horizontal force F is applied to the block of mass m2 . Determine the acceleration of the two block system and force exerted by mass m1 and m2 .​

Answer 1

Answer:

your answer is below

Explanation:

Two blocks with masses m

1

and m

2

are stacked on a horizontal smooth surface. Coefficient of friction between the blocks is μ. A force F is applied at angle θ with the horizontal on block of mass m

1

. Find the maximum force F so that the blocks move together.

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ANSWER

N=(m

1

g+Fsinθ)

F

f

=uN

Fcosθ−F

f

=m

1

a

Fcosθ−u(m

1

g+Fsinθ)=m

1

.......(1)

Fcosθ=(m

1

+m

2

)a ..............(2)

From equation 1 and 2:

Fcosθ−u(m

1

g+Fsinθ)=

m

1

+m

2

m

1

Fcosθ

F=

m

2

cosθ−u(m

1

+m

2

)sinθ

um

1

(m

1

+m

2

)g