Question

Two blocks A and B are placed on inclined planes as shown in Fig. 3(b). The block A weighs

1000 N. Determine minimum weight of the block B for maintaining the equilibrium of the system.

Assume that the blocks are connected by an inextensible string passing over a frictionless pulley.

Coefficient of friction µA between the block A and the plane is 0.25. Assume the same value for µB.​

Answer 1

Answer:

Deux blocs sont trop lourds alors ne décrochez pas plz

Answer 2

Given,

         Force body A = Force body B

Solution -

Net force on A = Net force on B

mg [ sinθ - µ cosθ ] = x [ $\frac{\sqrt{3} }{2}$ -$\frac{1}{4}$×$\frac{1}{2}$ ]

1000 [ $\frac{1}{2} - \frac{1}{4}$ ×$\frac{\sqrt{3} }{2}$ ] = x [ $\frac{\sqrt{3} }{2} -\frac{1}{4}$ × $\frac{1}{2}$ ]

$\frac{1000}{2} [ 1 - \frac{\sqrt{3} }{4} ] =\frac{x}{2} [ \sqrt{3} - \frac{1}{4} ]$

1000 [ 1 - $\frac{1.732}{4}$ ] × $\frac{1}{1.532} = x$

x = 370 N

So , the answer of this question is 370 N.

What is inclined plane ?

Inclined plane, simple machine consisting of a sloping surface, used for raising heavy bodies. The force required to move an object up the incline is less than the weight being raised, discounting friction. The steeper the slope, or incline, the more nearly the required force approaches the actual weight.

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