Physics, asked by naizasingla2000, 1 year ago

Two blocks 'A' and 'B' each of mass 'm' are placed on a smooth horizontal surface. Two horizontal force F and 2F are applied on the two blocks 'A' and 'B' respectively as shown in figure. The block A does not slide on block B. Then the normal reaction acting between the two blocks is (contact surface between blocks is smooth)


AionAbhishek: where is fig ?

Answers

Answered by wajahatkincsem
21
Hi thank you for asking the question
The reason they dont move is because of the frictional force between the two bodies
frictional force of A acting on body B = u1mg
Frictional force due to the surface acting on B = u2 ( m1 + m2 ) g
= F = 2F = 3F
Hope this answer suffice your question
Mark the answer as brainliest if it helped
Thank you
Answered by Yeshwanth1245
0

Hi thank you for asking the question

The reason they dont move is because of the frictional force between the two bodies

frictional force of A acting on body B = u1mg

Frictional force due to the surface acting on B = u2 ( m1 + m2 ) g

= F = 2F = 3F

Hope this answer suffice your question

Mark the answer as brainliest if it helped

Thank you

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