two blocks A and B each of mass m are placed on a smooth horizontal surface . two horizontal forces F and 2F are applied on both the blocks A and B respectively. Block A does not slide over block B. Then the normal reaction force acting between the blocks is? a)F B)F/2 C)F/(sqrt of 3) d) 3 F answer is 3F. Can anyone guide me how to get there?
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N=mg=F
so,force applied on both blocks is 3F.
so,force applied on both blocks is 3F.
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