Two blocks A and B having masses of 10kg each is placed on the ground. One have an area of 10 and 50 sq m respectively. What can we conclude about the pressure exerted on the ground by A and B?
Answers
Horizontal force, F = 600 N
Mass of body A, m₁ = 10 kg
Mass of body B, m2 20 kg
Total mass of the system, m = ml +
m2 = 30 kg
Using Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:
F = ma
Fma=600
30
20m/s²
When force F is applied on body A: The equation of motion can be written as: F - T = m₁a
T = F (m₁)a
= 600 - 10 × 20 = 400 N (i)
When force F is applied on body B: The equation of motion can be written
F-T= m₂a
T = F - (m₂)a
T = 600 20 × 20 = 200 N (ii)
which is different from value of T in case (i). Hence our answer depends on which mass end, the force is applied.
Explanation:
Horizontal force,F=600 N
Mass of body A, m
1
=10 kg
Mass of body B, m2=20 kg
Total mass of the system, m=m1+m2=30 kg
Using Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:
F=ma
a=
m
F
=
30
600
=20m/s
2
When force F is applied on body B:
The equation of motion can be written as:
F−T=m
2
a
T=F−(m
2
)a
T=600−20×20=200 N (ii)
which is different from value of T in case (i). Hence our answer depends on which mass end, the force is applied.