Question

Two blocks A and B kept on smooth horizontal
surface are acted upon by few forces as shown.
initially block A is moving towards right with
constant speed and block B is at rest. After the
application of forces on both as shown
12 N
12 N
5 N 10 N
AK
7 N 2N
B 112​

Answer 1

Answer:As block A does not slide on block B this means both blocks have the same acceleration along horizontal.

Net force on the system is 2F−F=F

Therefore, Acceleration is F/(m+m)=F/2m.

Now taking of individual blocks. Let Normal between block be N.

Block on right:

Along Horizontal: 2F−Ncos60=ma

⇒2F−m(F/2m)=N(1/2)

⇒  

2

3

​

F=  

2

1

​

N

⇒N=3F

Just to check we can calculate N at block on right also;

Ncos60−F=ma

⇒F+m(F/2m)=N(1/2)

⇒  

2

3

​

F=  

2

1

​

N

⇒N=3F

Explanation: