Question

Two blocks A and B kept on smooth horizontal surface are acted upon by honzontal forces as shown below The net force acting will be zero on
​

Answer 1

Answer:

As block A does not slide on block B this means both blocks have the same acceleration along horizontal.

Net force on the system is 2F−F=F

Therefore, Acceleration is F/(m+m)=F/2m.

Now taking of individual blocks. Let Normal between block be N.

Block on right:

Along Horizontal: 2F−Ncos60=ma

⇒2F−m(F/2m)=N(1/2)

⇒  

2

3

​  

F=  

2

1

​  

N

⇒N=3F

Just to check we can calculate N at block on right also;

Ncos60−F=ma

⇒F+m(F/2m)=N(1/2)

⇒  

2

3

​  

F=  

2

1

​  

N

⇒N=3F

Explanation: