Physics, asked by kartheek7264, 8 months ago

Two blocks A and B of equal masses ( m= 10kg) are connected by a light spring of spring constant k = 150 N/m. The system is in equilibrium. The minimum value of initial downward velocity v of the block B for which the block A bounce up is ..........

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Answered by Lueenu22
4

\bf\huge\ Question:-

Two blocks A and B of equal masses ( m= 10kg) are connected by a light spring of spring constant k = 150 N/m. The system is in equilibrium. The minimum value of initial downward velocity v of the block B for which the block A bounce up is ..........

\bf\huge\ Answer:-

Two blocks A and B of equal masses ( m= 10kg) are connected by a light spring of spring constant k = 150 N/m. The system is in equilibrium. The minimum value of initial downward velocity v of the block B for which the block A bounce up is ..........150kn

Answered by BlashX
3

Answer:

Explanation:

By energy conservation.

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