Physics, asked by anukumarianugya, 7 months ago


Two blocks A and B of mass
2m and 3 m
placed
a smooth horizontal
surface
connected with a
light Spring. Spring's natural
length
is l. The two
blocks are given the
velocity v

find
the (Vmax) A​

Answers

Answered by SejalDewangan
0

Answer:

The energy stored in the spring exists in the form of the potential energy and it is given as:

PE=

2

1

kx

2

When the block is left from maximum compression, the potential energy gets converted into kinetic energy of the block.

KE=

2

1

mv

2

At maximum compression

KE=PE

2

1

kx

2

=

2

1

mv

2

⇒x=

k

m

v

The magnitude of velocity will be the same but the direction will be opposite.

solution

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SIMILAR QUESTIONS

star-struck

Two masses m and 2m are connected by a spring having constant k as shown in the figure. The minimum compression in the spring from its natural length so that the block of mass 2m leaves contact with the surface is (n+1)

k

mg

. The value of n is:

431859

expand

Medium

View solution

>

In the ideal pulley-particle system shown, the mass m

2

is connected with a vertical spring of spring constant K. (m

2

>m

1

). If the mass

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