Physics, asked by DEVILRUDRA, 2 months ago

Two blocks A and B of mass 2m and 3m respectively are connected by a massless string. The whole system is suspended by a massless spring as shown in figure. The magnitude of acceleration of A and B immediately after the string is cut are respectively​

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Answered by Anonymous
5

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Answered by nirman95
1

Given:

Two blocks A and B of mass 2m and 3m respectively are connected by a massless string. The whole system is suspended by a massless spring as shown in figure.

To find:

The magnitude of acceleration of A and B immediately after the string is cut are respectively?

Calculation:

In this type of questions, always draw the free body diagram of both the blocks before and after cutting the string.

Diagram 1: Before cutting string

Diagram 2: After cutting string

Before cutting string:

For block A:

2mg + T = kx \:  \:  \: .....(1)

For block B:

3mg  = T \:  \:  \:  \:  \: .....(2)

So, putting value of T :

 \implies \: 2mg + 3mg= kx

 \implies \:  kx  = 5mg \:  \:  \:  \: ......(3)

After cutting string:

For block A:

2mg - T = 2m(a_{1})

 \implies \: 2mg - 5mg= 2m(a_{1})

 \implies \:  - 3mg= 2m(a_{1})

 \implies \:  a_{1} =  -   \dfrac{3g}{2}

 \boxed{ \implies \:   | a_{1}|  =   \dfrac{3g}{2} }

For block B:

Block B is falling freely, so it's acceleration will be simply "g".

Hope It Helps.

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