Two blocks A and B of masses 1.5kg and 0.5kg respectively are connected by a massless inextensible string passing over a frictionless pulley as shown in the figure. Block A is lifted until block B touches the ground and then block A is released. The initial height of block A is 80cm when block B just touches the ground. The maximum height reached by block B from the ground after the block A falls on the ground is
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Let velocity of B and A after collision has magnitude v.
At the time of collision tension =T
Impulse provided by tension =∫Tdt
Consider change of momentum of (B + bullet)
mu−∫Tdt=2mv ……… (i)
Consider change of momentum A
∫Tdt=3mv …………..(ii)
From (i) and (ii),
⟹mu=5mv
⟹v=u/5
Hence, Impulse: ∫Tdt=3mv
⟹3m(u/5)=3mu/5
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