Question

Two blocks A and B of masses 10 kg and 12 kg respectively are kept on a rough wedge of inclination 30°and 60° respectively. The coefficient of friction between the block A and wedge is 0.6 while that between Band the wedge is 0.3. The blocks are connected by a light inextensible thread. The wedge is fixed with respect to ground. Tension in the thread connecting A and B is (take g = 10 m/s2)

Answer 1

Answer:

answer will be 67.98

Explanation:

hope it help

Answer 2

Given,

Mass of Block A,$m_{A}$=10 kg

Mass of Block A,$m_{B}$=12 kg

Inclination of A on wedge= 30°

Inclination of B on wedge= 60°

Coefficient of friction between the block A and wedge is 0.6

Coefficient of friction between the block B and wedge is 0.3

To find,

Tension (T) in thread connecting A and B

Solution,

Total mass of the blocks = $m_{A}$ + $m_{B}$

⇒Total mass of the blocks= 10 +12

⇒Total mass of the blocks=22 kg

Using the formula,

Tension, T= mg+ma

Hence,

T-(5)(g)-(3$\sqrt{3}$)(g)=10($\frac{3\sqrt{3}-6.8 }{Total mass of the blocks}$)

⇒T=10($\frac{3\sqrt{3}-6.8 }{Total mass of the blocks}$)+(5)(g)-(3$\sqrt{3}$)(g)

⇒T=10($\frac{3\sqrt{3}-6.8 }{22}$)+(5)(g)-(3$\sqrt{3}$)(g)

On substituting value of g as 10 m/s²

⇒T=10($\frac{3\sqrt{3}-6.8 }{22}$)+(5)(10)-(3$\sqrt{3}$)(10)

⇒T=94.67 N

Hence, the tension in the thread connecting A and B is 94.67 N