Question

Two blocks A and B of masses 5 kg and 3 kg
respectively rest on a smooth horizontal surface
with B over A. The coefficient of friction between A
and Bis 0.5. The maximum horizontal force
(in kg wt.) that can be applied to A, so that there
will be motion of A and B without relative slipping, is​

Answer 1

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Explanation:

block B is over block A, so normal force between the blocks will be weight of block B. =30N.

so maximum friction force that can be generated is f=μ.N=0.5×30=15N

so maximum acceleration of block B is

m

f

=

3

15

=5m/s

2

so minimum acceleration of both the blocks can be 5m/s

2

if both blocks don't want to move together.

so minimum force that required for relative motion is m.a=8×5=40N

means force should be less then 40N, converting to (in kg wt.)(divide by 10) we get maximum force is less then 4kg wt.

so from the above options we found option B as maximum but less then 4, so option B is answer.