Question

Two blocks A and B of masses m. I kg and m - 3 kg are kept on the table as shown in figure. The collicien
of friction between A and B is 0.2 and between B and the surface of the table is also 02 The maximum one
that can be applied on B horizontally, so that the block A does not slide ove the block B is (Takeg = 10 m/s)​

Answer 1

The maximum force that can be applied on the horizontally is 16 N.

Explanation:

Given data:

Mass of A block =  1 Kg

Mass of B block =  3 Kg

Coefficient of friction between the blocks = 0.2

g = 10 m/s

a  (Amax) =  μg =2 m/s  

F - 8 = 4 \times 2F−8=4×2

F = 16 N

Thus the maximum force that can be applied on the horizontally is 16 N.

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If 1 cm  of wood weighs, find the weight of a wooden block whose length is

10 cm, breadth is 5 cm and height is 3 cm.​

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