Question

two blocks a and b of same mass and surface finish are sliding on same surface . area of contract of a is twice that of b .frictional force between a and the surface is

Answer 1

Answer:

As block A does not slide on block B this means both blocks have the same acceleration along horizontal.

Net force on the system is 2F−F=F

Therefore, Acceleration is F/(m+m)=F/2m.

Now taking of individual blocks. Let Normal between block be N.

Block on right:

Along Horizontal: 2F−Ncos60=ma

⇒2F−m(F/2m)=N(1/2)

⇒3/2F = 1/2 N

⇒N=3F

Just to check we can calculate N at block on right also;

Ncos60−F=ma

⇒F+m(F/2m)=N(1/2)

⇒ 3/2f=1/2N

⇒N=3F

Explanation:

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Answer 2

The frictional force between block A and the surface will be same as that between block B and surface.

• The frictional force is given by:

$f = \mu \times n$

Where

$\mu$

is the frictional coefficient and n is the normal force.

• The normal force only depends on the mass of the body and the acceleration due to gravity.
• Since the mass of the two blocks is equal and g is also constant, therefore the frictional force between the two block and the surface will be same as the frictional coefficient is same for both of them.
• Frictional force is independent of area untill and unless the area is very very smal.