Question

Two blocks are in contact on a frictionless table. One has mass m and the other 2m. A force F is applied on 2m as shown in figure. Now the same force F is applied from the right on m. In the two cases the ratio of force of contact between the two blocks will be (1) 1 : 1 (2) 1 : 2 (3) 2 : 1 (4) 1 : 3

Answer 1

Answer:If F is the applied force then acceleration of the system is  

2m+m F =  3m F

​  

Now when we apply the force from the left, the force applied on the block m is  

3m F m= 3 F

​ . This will be the force in the contact.

When we apply the force from the right from on the block will be  

3m F2m=  3 2F

​  

, this will be the force on the contact then.

So the ratio is  

3 F :  3 2F =1:2

Hence,

option B is correct answer.

Explanation:

Answer 2

Answer:

If F is the applied force then acceleration of the system is  

2m+m

F

​  

=  

3m

F

​  

 

Now when we are applying the force from the left, the force applied on the block m is  

3m

F

​  

m=  

3

F

​  

. This will be the force in the contact.

When we apply the force from the right from on the block will be  

3m

F

​  

2m=  

3

2F

​  

, this will be the force on the contact then,

So the ratio is  

3

F

​  

:  

3

2F

​  

=1:2

Explanation: