Question

Two blocks are kept on a smooth fixed slopes as shown.
2kg block goes down with an acceleration of 2m/s?.
The value of m is.
THE
2kg
m
90°
370​

Answer 1

Answer:

not a correct question???

Answer 2

The correct answer is (1) 0.8 kg.

The missing value "m" can be found by using the principles of mechanics and Newton's second law of motion.

Newton's second law states that the force acting on an object is equal to its mass multiplied by its acceleration:

F = ma

Since the 2 kg block is going down the slope with an acceleration of 2 m/s^2, the force acting on it can be calculated as follows:

F = ma = 2 kg * 2 m/s^2 = 4 N

This force can be resolved into components acting parallel and perpendicular to the slope. The component acting parallel to the slope is equal to the force of gravity acting on the block, which is m * g * cos(Θ), where m is the mass, g is the acceleration due to gravity, and Θ is the angle of the slope.

m * g * cos(Θ) = 4 N

Rearranging and substituting known values, we get:

m = 4 / (g * cos(90 - Θ))

We can find that for an angle of 37 degrees, the value of m is approximately 0.8 kg.

For more such questions on acceleration: https://brainly.in/question/12173183

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[ The complete question is as follows:

Two blocks are kept on a smooth fixed slope as shown

2kg block goes down with an acceleration of 2m/s?

The value of mis.THq 2kg 90°

37

(1) 0.8 kg

(2) 1 kg

(3) 2 kg

(4) 1.2 kg​ ]