Question

Two blocks of equal mass are tied with light strong which passes over a mindless pulley As shown. The magnitude of acceleration of the centre of mass of both blocks is

Answer 1

Answer:

0.5 m/s  ( angle = 37°)

Explanation:

A particle is moving with a velocity of 0.4 m/s is subjected to an acceleration of 0.15 m/s^2 for 2 sec in a direction at right angles to its direction of motion .find the resultant velocity

Velocity = 0.4 m/s

acceleration of 0.15 m/s² at 90° angle

Initially Velocity at right angle = 0 m/s

t = 2sec

Velocity at right angle = 0 + 0.15*2 =  0.3 m/s

acceleration in direction of motion = 0 m/s

Velocity in direction of motion = 0.4 m/s at t = 2

Velocity at t - 2sec = √(0.4)² +(0.3)²  =  √0.25 = 0.5 m/s

Angle = α => Tanα = 0.3/0.4 => Tanα = 0.75 => α = 36.87°

=> α = 37° (approx)

Resultant Velocity = 0.5 m/s at angle of 37°  to initial Direction of motion

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