Question

Two blocks of equal masses of lead and copper are immersed in the water.they experience the boyant forces F1 and F2 respectively. What will be the ratio of F1 and F2 (>,= or <1)?​

Answer 1

sorry for giving you , wrong answer

Answer 2

Given:

Two blocks of equal masses of lead and copper are immersed in the water. They experience the buoyant forces F1 and F2 respectively.

To Find:

What will be the ratio of F1 and F2 (>,= or <1)?​

Solution:

Since, we know that-

Buoyant force is given by;

$F = \rho .g.V$ ,

where, ρ is the density of fluid , g is the acceleration due to gravity and V is the volume of the displaced fluid.

therefore, here the buoyant force is related to the volume of water displaced, not the mass or density of the material. Since lead and copper both displace the same volume of water, implies the buoyant force is the same on both.  

As the lead and copper blocks displace the same volume of water, the buoyant force on each is the same.

Hence, F1 : F2 = 1 : 1 = 1