Question

Two blocks of mass 1 kg and 2 kg are connected by a b of mass 1 kg the blocks are placed on a horizontal surface block of mass 1 kg is pulled by a horizontal force f of magnitude 8n then acceleration=?,tension in string B=?

Answer 1

Answer:

the external force acting on the system is 8N hence it produces an acceleration a = F(net)/m(total)

a = 8/ 2+1+1 = 8/4 = 2 m/s2

now the force = tension at point B is due to combine mass of string and block of 2kg

hence TB = (2+1) x 2 = 6N

and tension at A TA

= 2 x 2 = 4N.

hence,

the tension at Aand B are (4,6) newton.