Two blocks of mass 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14m/s to the heavier block in the direction of the lighter block. The velocity of the centre of mass is : (a) 30m/s (b) 20m/s (c) 10 m/s (d) 5 m/s
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Velocity of centre of mass = m1v1 + m2v2 / m1+m2
= 10(14)+4(0)/10+4 = 10*14/14 = 10 m/s
Therefore the centre of mass velocity = 10 m/s
Option C
= 10(14)+4(0)/10+4 = 10*14/14 = 10 m/s
Therefore the centre of mass velocity = 10 m/s
Option C
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2
hey!! good morning!!
option c is ans
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