Two blocks of mass 10kg and 20kg are connected by a light string as shown in the figure. If two forces of 80N and 20N are exerted on the system the net acceleration of 10kg mass will be
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Answered by
2
Answer:
Hence,
For 10kg: T=ma
=10×12
=120N............(1)
For 20kg F−T=ma
200−120=20α
80=20a
a=4ms
∴ acc of 20kg=4ms
−2
Answered by
0
Answer:
2m/ square
Explanation:
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