Two blocks of mass 2kg and 4kg are accelerated with same acceleration by a force 10N on a smooth horizontal surface. Then the spring force between the two blocks will be
pls see the attach ment and tell me y s=2a. it would helpful
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Answer:
10/3 N
Explanation:
Given
f = 10N
Masses = 2kg and 4kg
now,
f = Mass*Acceleration
= (2+4)* a
= 6a
a = f/6
It is given that f = 10N
a = 10/6 m/s^2
Spring force T = mass * acceleration
T = 2a
we need to consider the mass of the object which is exerting the force. here, object with mass 2kg is the one exerting the force on the object with mass 4kg, therefore we take mass as 2kg
T = 2*10/6
T = 10/3 N
Hope it helps..
Thank you.!
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