Question

Two blocks of mass 2kg are connected by a massless ideal spring of spring constant k is equal to 10 newton per metre dot the upper blogger suspended from roof by a light string a the system shown shown is in equilibrium the string a is now cut the acceleration of upper block just after the spring is cut will be

Answer 1

Answer:

The acceleration of upper block just after the spring is cut will be 20 ms

Explanation:

According to the problem two blocks let b1 and b2 has the same mass of 2kg

The spring constant k= 10 N/m

Let g= 10 m/s

Now when the system is in equilibrium

k= b2g

k=2×10

k=20

T = b1g +k

T= 20+20=

T=40

Now according to the problem when a is cut  it will be removed the tension that balances b1g + kx.

Therefore the acceleration = 40/2 =20m/s