Question

Two blocks of mass 4 kg and 6 kg are placed in contact
with each other on a frictionless horizontal surface. If we
apply a push of 5 N on the heavier mass, the force on the
lighter mass will be
5N
6 kg
4 kg
(a) 5 N
(C) 2 N
(b) 4N
(d) None of the above​

Answer 1

Answer:

RIGHT ANSWER IS 2N.

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Answer 2

Answer:

In this problem, we have two blocks of mass, 4 kg and 6 kg, that are in contact with each other on a frictionless horizontal surface. We want to find the force on the lighter mass when a push of 5 N is applied to the heavier mass.

Explanation:

Since the surface is frictionless, the two blocks will move together as a single unit. Therefore, the acceleration of the two blocks will be the same. We can use Newton's second law to relate the force applied to the acceleration of the two blocks:

F = ma

Where F is the net force applied to the two blocks, m is the total mass of the two blocks, and a is the acceleration of the two blocks.

To find the acceleration of the two blocks, we need first to find the net force applied to the two blocks. The 5 N force is applied only to the 6 kg block, so the net force applied to the two blocks is 5 N. Therefore, we have:

5 N = (4 kg + 6 kg) a

Solving for a, we get:

a = 5 N / 10 kg = 0.5 m/s^2

Since the two blocks move together, the force on the lighter mass equals the force applied to the heavier mass. Therefore, the force on the lighter mass is also 5 N, corresponding to option (a) in the given choices.

In summary, when a push of 5 N is applied to the heavier mass, the force on the lighter mass is also 5 N, and the correct option is (a).

To learn more about horizontal surfaces, click on the link below.

https://brainly.in/question/120925

To learn more about the force, click on the link below.

https://brainly.in/question/23858054

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