Question

two blocks of mass 40 kg in 30 kg are connected by the weight loss is string passing over a frictionless Pulley as shown in the figure the acceleration of the system would be​

Answer 1

Explanation:

30 kg block will rise and 40 kg block will go down

Answer 2

Answer:

, m1=40g

m2=30kg,θ=30∘

Let T be the tension in the string and a be the acceleration of the system. Their equations of motion are m1sin30∘-T=m1a…(i)

T-mgsin30∘=m2a…(ii)

Adding (i) and (ii), we get

(m1+m2)a=(m1-m2)gsin30∘

Substituting the given values, we get

(40+30)a=(40-30)×9.8×

1

2

=49

a=

49

70

=0.7ms-2

Explanation:

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