two blocks of mass 4kg and 2kg are placed side by side on a smooth horizontal surface. A horizontal force of 20N is applied on 4kg block.
Find A) the acceleration of each block
B) normal reaction on the block B due to AA
a)10/3m/s²,20/3N
b)15/3m/s²,25/3N
c)25/3m/s²,15/3N
d)20/3m/s²,10/3N
need explaintion.if explanation is there I will mark as brainlist
Answers
Answered by
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Explanation:
The free body diagram of both the blocks are as shown in the figure.
a=
4+2
F
=
4+2
20
=
3
10
Using ΣF
x
=ma
x
For 4kg block, 20−N=4a=4×
3
10
N=20−
3
40
=
3
20
N
This can also be solved as below
For 2kg block, N=2a=2×
3
10
=
3
20
N
Here, N is normal reaction between the two blocks.
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