Question

Two blocks of mass 4kg and 6kg are attached by a spring constant k=200N/m, both blocks are moving with same acceleration. Find elongation in spring

Answer 1

Answer:

Hence, extension of spring is 30cm

Explanation:

Answer 2

Answer:

Given:

Mass of two blocks = 4 kg and 6

Spring constant k = 200 N/m

To find:

Elongation in the spring if the two blocks are moving with same acceleration.

Solution:

Let the elongation in the spring = 6 kg

And the acceleration be a m/s^2

For 6 kg block, as observed from the FBD the equation will be:

20 - kx = 6a

(1)

For the 4 kg block, the equation will be:

kx = 4a (2)

On adding both the equations we get:

20 = 10a

a = 2 m/s^2

From equation 2:

kx = 4a

x=0.04m

Hence, elongation of the spring is 2 m.

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