two blocks of mass m = 2 kg and M = 5kg are in contact on a frictionless table. A horizontal force ( = 35 N ) is applied to m. find force of contact between the block, will the force of contact remain same if F is applied to M?
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Hey...mate here is yur ans...
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⏩ As the blocks are rigid under the action of a force F, both will move with same acceleration
⏩ a = F / m + M = 35 / 2 + 5 =5 m/s^2
⏩ force of contact RM = Ma = 5 × 5 = 25 N.
⏩ if the force is applied to M then its action on m will be
Rm = ma = 10 N.
⏩ From the problem it is clear the acceleration does not depends on the fact that whether the force is applied to m or M, but force of contact does.
♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦
HOPE IT HELPS U✌
♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦
⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
⏩ As the blocks are rigid under the action of a force F, both will move with same acceleration
⏩ a = F / m + M = 35 / 2 + 5 =5 m/s^2
⏩ force of contact RM = Ma = 5 × 5 = 25 N.
⏩ if the force is applied to M then its action on m will be
Rm = ma = 10 N.
⏩ From the problem it is clear the acceleration does not depends on the fact that whether the force is applied to m or M, but force of contact does.
♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦
HOPE IT HELPS U✌
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