Two blocks of mass m = 5 kg and M = 10 kg are connected by a string passing
over a pulley B as shown. Another string connects the centre of pulley B to the
noor and passes over another pulley A as shown. An upward force F is applied
at the centre of pulley A. Both the pulleys are massless.
Find the acceleration of blocks m and M if Fis:
(a) 100 N
(b) 300 N
(C) 500 N (take g = 10 m/s)
(
в
mN
Answers
Answer:
Explanation:For Few=300N
T=F/4=75 Tmg, M will be remain stationary on the floor,whereas m will move.So Acceleration of m, a=(T-mg)/m=(75-50)/5 = 5m/s2.
Answer:
(a). If the force is 100 N then the blocks do not accelerate.
(b). If the force is 300 N then the block m will accelerate with 5 m/s².
(c). If the force is 500 N then both the block will be accelerate with 15 m/s² and 2.5 m/s².
Explanation:
Let the tension in the string passing over A is T₀.
The tension in the string passing over B is T.
According to FBD,
So,
(a). If force is 100 N
We need to calculate the weight of the both block
Weight of the block m = 50 N
Weight of the block M= 100 N
We need to calculate the tension
Using formula of tension
Put the value of F
Here, T<mg and T<Mg
So, both the block remain stationary on the floor
(b). If the force is 300 N
We need to calculate the tension
Using formula of tension
Put the value of F
Here, T>mg and T<Mg
So, block M will remain stationary on the floor and block m will move
We need to calculate the acceleration
Using formula of acceleration
(c). If the force is 500 N
We need to calculate the tension
Here, T>mg and T>Mg
So, both the block will accelerate upward
We need to calculate the acceleration of m block
We need to calculate the acceleration of M block
Hence, (a). If the force is 100 N then the blocks do not accelerate.
(b). If the force is 300 N then the block m will accelerate with 5 m/s².
(c). If the force is 500 N then both the block will be accelerate with 15 m/s² and 2.5 m/s².