Two blocks of mass m1 = 1kg and M2 = 2 kg. are in contact with each other on a frictionless table . a force of 10n is acting on m1 and m2 , what is the acceleration of m1 and m2. what is the value of action and reaction
Answers
Answer:
Method 1 :
Since the two blocks always remain in contact with each other, they must move with the same acceleration. Using Newton's second law, we get
For block m
1
:F−N=m
1
a......(i)
For block m
2
:N=m
2
a......(ii)
On adding the two equations, we get
F=(m
1
+m
2
)a⇒a=
m
1
+m
2
F
Substituting the value of a in (ii), we get N=m
2
a=
m
1
+m
2
Fm
2
Method 2 :
The situation may be considered as follows: Instead of drawing the free-body diagrams of each block, we can draw the free-body diagram of both blocks together as shown in Fig.6.33.
The net force acting on the system is F, and the total mass of the system is
m
1
+m
2
. Thus, a=
m
1
+m
2
F
To find out the normal reaction N between the two blocks, we can imagine the following; Block m
2
is moving with an acceleration a; therefore, the net force acting on it must be m
2
a, which is nothing but the normal reaction applied by the block m
1
. Thus,
N=m
2
a=
m
1
+m
2
m
2
F
Explanation: