Two blocks of mass m1 = 20 kg and m2 = 12kg are connected by a metal rod of mass 8 kg. The system is pulled vertically up by applying a force of 480 n as shown. The tension at the midpoint of the rod is:
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The total system mass is M = 40 kg
M*a = F - M*g
40kg * a = 480N - 40kg * 10m/s² = 80 N
a = 2 m/s²
At the midpoint of the rod, half of the rod and M2 are below, having total mass
m = 16 kg
so tension T = m(g+a) = 16kg * (10 + 2)m/s² = 192 N ◄ (c)
Explanation:
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