Question

two blocks of mass M1=20 kg and M2=12kg are connected to to metal rod of mass 8 kg . the system is pulled vertically up by applying a force of 480N .the tension at the midpoint of the rod is

Answer 1

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✭Question✭

two blocks of mass M1=20 kg and M2=12kg are connected to to metal rod of mass 8 kg . the system is pulled vertically up by applying a force of 480N .the tension at the midpoint of the rod is

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$\text{\large\underline{\orange{Solution:-}}}$

The total mass of the system $\text{\large\underline{\pink{=20+12+8=40kg.}}}$

The gravitational force 'g′

= 10m/$s^{2}$ $\bold{ma =F −mg}$

$\bold{40a=480−40×10}$

a=2m/$S^{2}$

At the midpoint of the rod, half of the rod and $M^{2}$are below, having total mass of 4+12=16kg.

$\bold{Therefore,}$

$\bold{Tension,\:T=m(g+a)=16(10+2)}$

$\large\red{\underline{{\boxed{\textbf{Answer = 192N}}}}}$

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Answer 2

$\huge{ \underline{ \bold{ᴀɴsᴡᴇʀ....{ \heartsuit}}}}$

The total mass of the system \text{\large\underline{\pink{=20+12+8=40kg.}}}

=20+12+8=40kg.

The gravitational force 'g′

= 10m/s^{2}s

2

\bold{ma =F −mg}ma=F−mg

\bold{40a=480−40×10}40a=480−40×10

a=2m/S^{2}S

2

At the midpoint of the rod, half of the rod and M^{2}M

2

are below, having total mass of 4+12=16kg.

\bold{Therefore,}Therefore,

\bold{Tension,\:T=m(g+a)=16(10+2)}Tension,T=m(g+a)=16(10+2)

\large\red{\underline{{\boxed{\textbf{Answer = 192N}}}}}

Answer = 192N