Question

Two blocks of mass m1 = 20kg and m2 =12kg are connected by a metal rod of mass 8 kg. The system is pulled vertically up by applying a force of 480 n as shown. The tension at the mid - point of the rod is

Answer 1

Answer:

192 N

Step by step explanation:

The total mass of the system = 20 + 12 + 8 = 40 kg.

The gravitational force 'g' = 10 $m/s^2$

$ma=F-mg\\40a=480-40*10\\a=2\:m/s^2$

At the midpoint of the rod, half of the rod and M2 are below, having total mass of 4 + 12 = 16 kg.

Therefore, Tension, $T=m(g+a)=16(10+2)=192\:N$

Answer 2

Answer:

it is right as far I think