Two blocks of masses 10 kg and 20 kg are placed on the x-axis. The first mass is moved on the axis by a distance of 2 cm. By what distance should the second mass be moved to keep the position of the center of mass unchanged.
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ANSWER::
Two masses m₁ and m₂ are kept on X-axis.
m₁=10 kg m₂= 30 kg
x₁ = 2 cm x₂ = ?
m₁ is displaced by a distance of 2 cm.
Centre of mass = (m₁x₁+m₂x₂) / (m₁+m₂)
0 = (10x2+20x₂) / (10+20)
0 = (20+20x₂) / 30
0 = 20+20x₂
x₂ = -20 /20
x₂ = -1
So , m₂ should be displaced by a distance 1 cm towards left so , as to keep the position of centre of mass unchanged.
Hope it helps!
ANSWER::
Two masses m₁ and m₂ are kept on X-axis.
m₁=10 kg m₂= 30 kg
x₁ = 2 cm x₂ = ?
m₁ is displaced by a distance of 2 cm.
Centre of mass = (m₁x₁+m₂x₂) / (m₁+m₂)
0 = (10x2+20x₂) / (10+20)
0 = (20+20x₂) / 30
0 = 20+20x₂
x₂ = -20 /20
x₂ = -1
So , m₂ should be displaced by a distance 1 cm towards left so , as to keep the position of centre of mass unchanged.
Hope it helps!
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