Question

Two blocks of masses 10 kg and 30 kg are placed along a vertical line. The first block is raised through a height of 7 cm. By what distance should the second mass be moved to raise the center of mass by 1 cm?

Answer 1

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ANSWER::

Two masses m₁ and m₂ are kept in a vertical line.

m₁=10 kg                 m₂= 30 kg
y₁ = 7cm                   y₂ = ?

The centre of mass is raised by 1 cm.

Centre of mass = (m₁y₁+m₂y₂) / (m₁+m₂)

1 = (10x7₁+30y₂) / (10+30)

1 = (70+30y₂) / 40

40 = 70+30y₂

30y₂ = -30

y₂ = -1

So , m₂ = 30 kg body should be displaced 1 cm downward so , as to raise the centre of mass through 1 cm.

Hope it helps!

Answer 2

Explanation:

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